Goodwill Estate Pipes (Pic Heavy)

[spartan]

These are the before pictures of some pipes I got off of the Goodwill Auction website thing. Got these pipes for $10 + $13 shipping. I bought this lot because I wanted the Bulldog and the Ventilator.
I was lazy and took most these indoors.
Here's a quick shot of all of them.

From top to bottom:
Honeymaster

Kaywoodie Billiard (I'm still learning all the shapes. So if it's not a billiard then please correct me)

Kaywoodie Bulldog

Medico Ventilator

Honeymaster

This looks to have one of those stingers that I can just rip out. I look forward to doing so, but will smoke it with the stinger first.

Kaywoodie Billiard

Kaywoodie Bulldog

You'll see that this pipe has an overclocked thing-a-ma-jiger, but it does not affect the stem. When it's all screwed in it's perfect. So I hope I can cran it into position without affecting the stem alignment.

Medico Ventilator

Will post cleaned picks later, Still need to purchase some wax & Micromesh.

 

[cynyr]

Nice deal on those items, and the price was certainly right!
I dig the Bulldog most - I'm gonna have me a Rhodesian or a 999 or bust.

 

[ejames]

Good score! They all should shine up nicely!

 

[crpntr1]

Those will clean up good, I really like the bent billiard

 

[bubblehead33]

excellent find! i really dig the bulldog, very cool shape.

 

[gwynclan]

Nice score, got a little work ahead of you, but it will defiantly be worth it.

 

[markw4mms]

Nice score!

 

[spartan]

On a side note that marble chess board I was taking photos on is currently being repaired by me. There was a panel that came "unglued"
It's currently receiving an epoxy treatment.
I've never used it. /sigh

 

[adam12]

You need to send those babies to Cajundude.

 

[spartan]

They're just pipes not a complex math problem.
Find real values of the number a for which a.i is a solution of the polynomial equation

z4 - 2z3 + 7z2 - 4z + 10 = 0.

Then find all roots of this equation.
Solution
Since a.i is a solution of the equation, we have
(a.i)4 - 2(a.i)3 + 7(a.i)2 - 4(a.i) + 10 = 0
a4 + 2.i.a3 - 7a2 - 4.i.a + 10 = 0
a4 - 7a2 + 10 = 0 and 2a3 - 4a = 0
a2 = 2
a = sqrt(2) or a = - sqrt(2)
Now, we know that sqrt(2).i and - sqrt(2).i are roots of z4 - 2z3 + 7z2 - 4z + 10 = 0 .

This means that z4 - 2z3 + 7z2 - 4z + 10 is divisible by (z - sqrt(2).i)(z + sqrt(2).i) = z2 - 2.

The quotient is (z2 - 2 z + 5) . The roots of this polynomial are 1 + 2 i and 1 - 2 i.
The four roots of the given equation are

sqrt(2).i -sqrt(2).i 1 + 2 i 1 - 2 i.
I think I'll be fine.

 

[patiobum]

A lil clean up and you've got some sweet schmokin' pipes !!

 

[papipeguy]

I got my pipes from the Goodwill auction on Friday. Cleaning them now and hope to post pics this week. Enjoy your new pipes.

 

[pipeinhand]

NICE catch, will be fun cleaning them gems up.
@spartin, you have made a mistake in your calculations, the answer is 42.

 

[spartan]

And you have made a mistake in your spelling; it's SPARTAN!!! :twisted:
And I just copied that math problem from a google search lol. I can barely do Pre-Cal. Couldn't wrap my head around the concept. I'm sure now as a 24 year old I would have many more questions about everything in class than I did in my teens...
I'll be going back to school soon............-ish.

 

[1robert]

Good catch there pipeinhand! We all know that 42 is the answer to the ultimate question of Life, The Universe, and Everything...well, that and a good pipe filled with your favorite tobacco.

 

[tokerpipes]

I have seen several Ventalators on here and I dig the look of them. Nice find on all of them. Good luck on the clean up.